设y=ln[cos(1+3x^2)],则dy=

设y=ln[cos(1+3x^2)],则dy= 设y=ln(1+x^2)则dy= 设y=[cos (1/x)]^3,则dy＝ 设y=ln(x/1+x)-cot2x,求dy. 设y=cos^2(x+1),求dy 设y=ln(x)则dy=? 设函数y=ln(x³+1)求dy 设y=ln(1+e^-x)求dy 设 y=e^x - ln cos x.求dy 速度 设ln(x^2+y^2)=arctan(y/x),则dy/dx= 设y=arctan(a/x)+1/2[ln(x-a)-ln(x+a)],求dy|x=0 设 x/y=ln(y/x) ,求 dy/dx