作业帮计算I=∮1/x*arctan(y/x)dx+2/y*arctan(x/y)dy,L为圆周x^2+y^2=1,x^2+y
计算I=∮1/x*arctan(y/x)dx+2/y*arctan(x/y)dy,L为圆周x^2+y^2=1,x^2+y
函数y=arctan(1+x^2)求dy/dx
y=arctan(x+1)^1/2,求dy=?
设ln(x^2+y^2)=arctan(y/x),则dy/dx=
x^2+y^2=e^(arctan（y/x）),求dy/dx
arctan(y/x)=ln(sqrt(x^2+y^2)),请问dy/dx是什么?
ln√(x^2+y^2)=arctan(y/x)的导数dy/dx
y=arctan（x^2+1）
设函数y=arctan(1+x^2),求dy/dx.
y=2x*arctan(y/x),求y‘’
已知函数y(x)由方程arctan y/x=1/2ln(x^2+ y^2)确定,求dy.
y=(1+x^2)arctan x 用MATLAB求(d^2*y)/dx^2