已知α属于(π/4,3π/4),β属于(0,π/4),且cos(π/4-α)=3/5,sin(5π/4+β)=-12/1
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/11/09 04:49:04
已知α属于(π/4,3π/4),β属于(0,π/4),且cos(π/4-α)=3/5,sin(5π/4+β)=-12/13
求cos(α+β)
求cos(α+β)
α∈(π/4,3π/4),
α-π/4∈(0,π/2),
cos(π/4-α)=3/5
cos(α-π/4)=3/5
sin(α-π/4)=4/5
β∈(0,π/4)
π/4+β∈(π/4,π/2)
sin(π+π/4+β)=-12/13
-sin(π/4+β)=-12/13
sin(π/4+β)=12/13
cos(π/4+β)=5/13
cos(α+β)
=cos[(α-π/4)+(π/4+β)]
=cos(α-π/4)cos(π/4+β)-sin(α-π/4)sin(π/4+β)
=3/5*5/13-4/5*12/13
=15/65-48/65
=-33/65
α-π/4∈(0,π/2),
cos(π/4-α)=3/5
cos(α-π/4)=3/5
sin(α-π/4)=4/5
β∈(0,π/4)
π/4+β∈(π/4,π/2)
sin(π+π/4+β)=-12/13
-sin(π/4+β)=-12/13
sin(π/4+β)=12/13
cos(π/4+β)=5/13
cos(α+β)
=cos[(α-π/4)+(π/4+β)]
=cos(α-π/4)cos(π/4+β)-sin(α-π/4)sin(π/4+β)
=3/5*5/13-4/5*12/13
=15/65-48/65
=-33/65
已知α属于(π/4,3π/4),β属于(0,π/4),且cos(π/4-α)=3/5,sin(5π/4+β)=-12/1
α属于(0,π/2)且2sin²α-sinαcosα-3cos²α=0求sin(α+π/4)/sin
已知a属于(0,π/2),且2sin^2 a-sin a cos a-3cos^2 a=0,求SIN(a+兀/4)/SI
已知α属于(π/4 π/6)且4cosν2α+17sinαcosα=0 1 求tan(α+π/4)
sin a/2=4/5,且a属于(π/2,π),求sin a,cos a的值
已知α,β属于(3π/4,π),sin(α+β)=-3/5,sin(β-π/4)=12/13,求cos(α+π/4)
已知α,β属于(0,π/2)且sinβ=cos (α+β)sinα,
已知α,β属于3π/4到π sin(α+β)=-3/5 sin(β—π/4)=12/13 求cos(α+π/4)=?
已知sinα+cosα=2/3,α属于(0,π),求sinα-cosα的值
已知向量a=(3sinα,cosα),b=(2sinα,5sinα-4cosα),α属于(3π/2,2π),且a⊥b.
1.已知sin2α=1/4,α属于(π/4,π/2),则 cosα-sinα=?2.已知sinα+cosα=1/3,0<
已知向量a=(3sinα,cosα),b=(2sinα,5sinα-4sinα),α属于(3π/2,2π),且a⊥b.