∫x sin (2分之x）dx

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/07/02 16:30:59

∫x sin (2分之x）dx

∫x sin (x/2）dx
=∫x d[-2cos(x/2)]
=-2xcos(x/2)-∫-2cos(x/2)dx
=-2xcos(x/2)+2∫cos(x/2)dx
=-2xcos(x/2)+4sin(x/2)+C

∫x sin (2分之x）dx ∫sin(x) cos^2(x)dx 不定积分∫sin(x^2)dx 求不定积分∫sin(x/2)dx 求不定积分：∫sin(x^2)dx ∫sinx/(cosx-sin^2x)dx ∫[(sin^2)x]dx求不定积分 ∫（1-sin^3x）dx 1.∫（sinxcosx）/（1+sin^2x）dx ∫sin²（x/2）dx=? 求不定积分∫[ln（sin X）]/(sin X)^2 dx的详解 ∫dx/[sin^2(x/2)cos^2(x/2)]