当X²+2Y²-6X+2√2*Y+10=0,求4Y2/2X

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/09 02:56:33

当X²+2Y²-6X+2√2*Y+10=0,求4Y2/2X
.
2√2*Y也就是2倍根号2乘以Y

把10拆成9和1,得
X²+2Y²-6X+2√2*Y+9+1=0
配方
X²-6X+9+2Y²2√2*Y+1=0
化简
X²-6X+9=(x-3)^2
2Y²2√2*Y+1=（√2Y+1）^2
所以原式化简为
(x-3)^2+（√2Y+1）^2=0
所以(x-3)^2=0
解得X=3
所以（√2Y+1）^2=0
解得Y=-√2/2
所以4Y^2/2X=1/3

当X²+2Y²-6X+2√2*Y+10=0,求4Y2/2X 已知4x²+y²-4x-6y+10=0,求（2x／3*√(9x)+y²√(x/y³ 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 已知x²+y²-4x+6y+13=0,求x²+2y/x²-3y²的值 |x+2y+3|+(2x+y)²=0求x²-xy+y² 已知x²+y²-6x+4y+13=0,求(2x-y)²-2(2x-y)(x+2y)+(x+ 求圆x²+y²-10x-10y=0 与 x²+y²-6x+2y-40=0 的公共已知x²+4x+y²-10y+29=0 求【x+2y】÷【x²-2y²】的值已知：x²+4x+y²-+6y+13=0,求x-2y/x²+y²的值. 2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y x²-2x+y²+6y+10=0,求—9(x+y)²+(3x-2y)(2y+3x)的值 x/y=2,求分式x²-xy+3y²/x²+xy+6y²