设数列an
设数列an
设数列{an}中,a1=2,an+1=an+n+1,则通项an=?
设数列{an}是公差不为零的等差数列
设数列an=n^2+λn,a1
设{an}与{bn}中一个是收敛数列,另一个是发散数列.证明{an±bn}是发散数列.
设数列{an}中,a1=2,a(n+1)=an+n+1,求an
设数列{an}满足:a1=1,an+1=3an,n∈N+.
设数列an满足a1=2 an+1-an=3-2^2n-1
设数列{an},a1=3,an+1=3an-2(n∈N*)
设数列an a1=3 3an+1-3an=2 则a100=
设数列{an}满足an+1/an=n+2/n+1,且a1=2
设数列{an},a1=3,a(n+1)=3an -2 (1)求证:数列{an-1}为等比数列