分式的乘除法计算：：x²-4y²/x²+2xy+y²÷x+2y/x²+

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/05 23:33:57

分式的乘除法计算：：x²-4y²/x²+2xy+y²÷x+2y/x²+xy

原式=[(x+2y)(x-2y)/(x+y)²]÷[(x+2y)/x(x+y)]
=(x+2y)(x-2y)x(x+y)/[(x+y)²(x+2y)]
=(x-2y)x/(x+y)
=(x²-2xy)/(x+y)

分式的乘除法计算：：x²-4y²/x²+2xy+y²÷x+2y/x²+ 分式的除法运算x²－4y²/x²+y²+2xy÷2y+x/x²+xy x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 计算:(1).(-2xy²)*(3x²y)² 1-x²+2xy-y² x/y=2,求分式x²-xy+3y²/x²+xy+6y² x²+y²+4x-8y+20=0,求分式x²-y²/xy的值分式乘除法：已知x-3y=0,求2x+y/x²-2xy+y²×(x-y)的值 3x²-4xy+y² 已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值代数分式一道题若x÷y=2,则分式（x²-xy+3y²)÷（x²＋xy＋6y² x²+y²+4x-8y+20=0,求(x²-y²)÷xy的解