1/(x-1)(x-3)+1/(x-3)(x-5)+1/(x-5)(x-7)+...+1/(x-97)(x-99)这道题

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/10/06 19:57:44

1/(x-1)(x-3)+1/(x-3)(x-5)+1/(x-5)(x-7)+...+1/(x-97)(x-99)这道题该怎么做?

1/(x-1)(x-3)+1/(x-3)(x-5)+1/(x-5)(x-7)+...+1/(x-97)(x-99)
=(1/2)[1/(x-3)-1/(x-1)+1/(x-5)-1/(x-3)+...+1/(x-99)-1/(x-97)]
=(1/2)[-1/(x-1)+1/(x-99)]
=49/(x-1)(x-99)

|X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 已知3x*x-x=1,求6x*x*x+7x*x-5x+2000 1x+2x+3x+4x+5x+6x+7x…+99x=100 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x 因式分解 (x+1)(x+3)(x+5)(x+7)+15 换元法 (x+1)(x+3)(x+5)(x+7)+15 (x-1)(x-3)(x-5)(x-7)-9 因式分解 1/(x-1)(x-3)+1/(x-3)(x-5)+1/(x-5)(x-7)+...+1/(x-97)(x-99)这道题解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) (2x-1)/(x-1)(x-2)=(x-5)/(x-2)(x-3) x/2x^2-11x-21=(x+7)/x^2-1