y=-x²+4x-7,x∈{0,1,2,3,4}
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
y=-x²+4x-7,x∈{0,1,2,3,4}
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
求下列函数的值域 (1) y=x²-2x,x∈{0,1,2,3} (2)y=x²-4x+6,x∈[]
(x+y)-(x+y)平方 因式分解 解方程 2x²=3x (3x-1)² - 4=0 5x-15x
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
已知集合A={(x,y)| (y-3)/ (x-1)=2,x,y∈R},B={(x,y)| 4x+ay=16,x,y∈
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知:x+y=-½,x-y=-7/2,求x-2(1/4x-1/3y²)+(-3/2x+1/3y
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(
2道数学题,求值域y=x^2-2x-3 ,x∈[0,3)y=-x^2-4x+1,x∈[-1,1]