作业帮一道国外的物理题,应该属于很简单的,很着急,Lasse (mass 55 kg) skies
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一道国外的物理题,应该属于很简单的,很着急,Lasse (mass 55 kg) skies
Lasse (mass 55 kg) skies downhill along a slope which is 45 m long and has an
angle of inclination of 17\x0e.The kinetic coefficient of friction between Lasse’s skies
and the snow is 0.16.The temperature for both the snow and the air is 0 \x0eC.
a) What is Lasse’s speed at the bottom of the slope,if he starts from rest?Air
resistance is neglected.
b) How far does Lasse slide along the horizontal section after the slope?
c) What is the maximum amount of snow that may melt under Lasse’s skies?
Lasse (mass 55 kg) skies downhill along a slope which is 45 m long and has an
angle of inclination of 17\x0e.The kinetic coefficient of friction between Lasse’s skies
and the snow is 0.16.The temperature for both the snow and the air is 0 \x0eC.
a) What is Lasse’s speed at the bottom of the slope,if he starts from rest?Air
resistance is neglected.
b) How far does Lasse slide along the horizontal section after the slope?
c) What is the maximum amount of snow that may melt under Lasse’s skies?
就是55KG的lasse沿17度斜坡下滑,坡长45m,动摩擦系数为0.16,雪和空气均为0度.
蒋势能转变为动能和热（摩擦做功）缺少一个冰的融化热
1、mgh＝mg*45*sin17＝0.5*m*V*V+45*mg*cos17*0.16,计算出即可
2、从1 得出的速度后动能转化为热
0.5 m*V*V＝mg*0.16*水平位移 计算出即可
3、直接能量守恒得出,mgh＝mg*45*sin17＝融化热*质量,假设冰刚好熔化为0度的冰.
蒋势能转变为动能和热（摩擦做功）缺少一个冰的融化热
1、mgh＝mg*45*sin17＝0.5*m*V*V+45*mg*cos17*0.16,计算出即可
2、从1 得出的速度后动能转化为热
0.5 m*V*V＝mg*0.16*水平位移 计算出即可
3、直接能量守恒得出,mgh＝mg*45*sin17＝融化热*质量,假设冰刚好熔化为0度的冰.