|-0.01|^-1/2(-5/8)^0+3log3^2+(lg2)^2+lg2*lg5+lg5同志们帮忙解一下
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/09/15 05:03:32
|-0.01|^-1/2(-5/8)^0+3log3^2+(lg2)^2+lg2*lg5+lg5同志们帮忙解一下
0.01^(-1/2)-log0.5底8+3^(log3底2)+(lg2)^2+lg2*lg5+lg5=?
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5
lg2(1+lg5)+(lg5)^2
lg2+lg5-log2(3)乘log3(2)
=(lg5)^2+lg2×lg5+lg2 =lg5×(lg5+lg2)+lg2麻烦问一下,这是咋做的
3+lg5+(lg2)^2
lg5(1-lg5)+2lg5根号2+lg2(1-lg5)
计算:(lg5)^2 +lg2 *lg5
(lg5)^2+lg5.lg2=
(lg2)^2+lg2*lg5+(lg5)^2=
2lg2(lg2+lg5)+2lg5得数
(lg5)平方+2*lg5*lg2+(lg2)平方