计算1/1x2+1/2x3+1/3x4+…+1/2009x2010的值,提示:1/1x2=1-1/2,1/2x3=1/2
已知x4+x3+x2+x+1=0,求1+x+x2+...+x2010的值
已知:|X1-1|+|X2-2|+|X3-3|+.+|X200292009|+|X2010-2010|=0 求x2010
1x2/1+2x3/1+3x4/1+.+2009x2010/1=? 2x4/1+4x6/1+6x8/1+.+2010x2
求线性方程组 x2-x3-x4=0 x1+x2-x3+3x4=1 x1-x2+x3+5x4=-1 x1+2x2-2x3+
X1+2X2-X3+X4=1
具体写出方程组:2x1+x2-x3+x4=1;x1+2x2+x3-x4=2;x1+x2+2x3+x4=3的通解
已知|x1-1|+|x2-2|+|x3-3|+...+|x2009-2009|+|x2010-2010|=0,求代数式x
求非齐次线性方程组的通解:2x1+x2-x3-x4=1;2x1+x2+x3-x4=1;4x1+2x2+x3-2x4=2
1+2x4-(x2+2x3)
设线性方程组(x1+2x2-2x3+2x4=2,x2-x3-x4=1 x1+x2-x3+3x4=a)
求齐次线性方程组x1+2x2+x3+x4+x5=1 2x1+4x2+3x3+x4+x5=2 -x1-2x2+x3+3x4
解方程组X2+X3+X4=1 X1+X2+X3=5 X3+X4+X5=-5 X4+X5+X1=-3 X5+X1+X2=2