连续可微函数F(t)满足 F(t)=∫∫x[1-F(x^2+y^2)/(x^2+y^2)]dxdy,x>=0,y>=0.
已知函数f(t)满足对任意实数x,y都有f(x+y)=f(x)+f(y)+xy+1,且f(-2)=-2
已知函数f(x)满足f(x+y)+f(x-y)=2f(x)f(y)(x∈R,y∈R),且f(0)≠1.
已知函数y=f(x)满足f(x)=2f(1x
若函数y=f(x)满足f(x+2)=f(x),且x在[-1,1]时,f(x)=x² 函数
8、设f(x)为可导函数,且满足∫0到x f(t)t^2 dt=f(x)+3x 求f(x)
f(x)为连续函数,∫(1-2)f(x)dx=1,F(t)= ∫(1-t)[f(y) ∫(y-t)f(x)dx]dy,则
对每一实数对(x,y),函数f(t)满足f(x+y)=f(x)+f(y)+f(xy)+1,若f(-2)=-2,试求满足f
已知函数f(x)满足f(2)=1/2,2f(x)f(y)=f(x+y)+f(x-y),则f(2012)=?
已知函数f(x)满足f(1)=1/4,f(x)+f(y)=4f(x+y/2)*f(x-y/2)则f(-2011)=?
f(x) 在定义域(0,正无穷)上是增函数,满足f(2)=1,f(xy)=f(x)+f(y).求不等式f(x)+f(x-
高数微积分方程. 函数f(t)在[0,+∞]连续且满足f(t)=e^(4πt^2)+∫∫f[根号下(x^2+y
三道微积分题目1.设f(x)的导函数连续且满足 [f(x)]^2=100 +∫(0到x) {[f(t)]^2+[f'(t