log(8)9 / log(2)3 这要用什么公式啊`?
log(8)9 / log(2)3 这要用什么公式啊`?
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]
(log(4)3+log(8)3)(log(3)2+log(9)8) 怎么个思路
(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(
log(2)(25)*log(3)(根号2)*log(5)(9)
计算:2log(2)3-log(2)9/8
(log(8)9)/log(2)3
log(2)9×log(3)4
log(2)9log(3)4等于
如何计算啊.(log底数4真数3+log底数8真数3)乘(log底数3真数2+log底数9真数2)=?
(LOG(3,4)+LOG(3,8))(LOG(2,3)+LOG(2,9))等于几 看的懂吧