化简(sin^4+cos^4+sin^2xcos^2x)/(2-sin2x)
sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos
化简cos^4x+sin^2xcos^2x+sin^2x
求函数f(x)=(sin^4x+cos^4x+sin^2xcos^2x)/(2-sin2x)的最小正周期、最大值和最小值
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
求函数f(x)=(sin^4x+cos^4x+sin^2xcos^2x)/2
求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域.
求函数y=2sin xcos x+2sin x+2cos x+4的值域
求函数f(x)=(sin^4x+cos^4x+sin^2xcos^2x)/(2-sin2x)的最小正周期,值域及单调增区
求函数f(x)=sin四次方x+cos四次方x+sin二次方xcos二次方x比上2-sin2x的最小正...
求函数fx=(sin^4x+cos^4x+sin^2x*cos^2x)/(2-sin2x)
化简:2cos2x+2sin^2 x+cos(-x)分之sin2x+sin(π-x)=___________
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x