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阅读下面材料:解答问题

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阅读下面材料:解答问题
已知;a、b、c是△ABC的三边,且满足a 2 c 2 -b 2 c 2 =a 4 - b 4 ,试判断△ABC的形状。
解:∵ a 2 c 2 -b 2 c 2 =a 4 - b 4                                                                    
      ∴ c 2 (a 2 -b 2 )=(a 2 +b 2 )(a 2 -b 2 )                          ②
      ∴ c 2 = a 2 +b 2                                                                                   
      ∴ △ABC是直角三角形问题:
(1)上述解题过程,从哪一步开始出现错误:_________ (写出序号),
  错误的原因是;________________________ 。
(2)请你正确解答:
(1) ③ ;(a 2 -b 2 )可以为0 ;
(2) ∵ a 2 c 2 -b 2 c 2 =a 4 -b 4
     ∴ c 2 (a 2 -b 2 )=(a 2 +b 2 )(a 2 -b 2
    ∴ c 2 (a 2 -b 2 )-(a 2 +b 2 )(a 2 -b 2 )=0 
    ∴ 〔c 2 -(a 2 +b 2 )〕(a 2 -b 2 )=0
    ∴ c 2 - a 2 -b 2 =0 或 (a 2 -b 2 )=0 。
  又 a 、b、c 是三角形的边
    ∴c 2 = a 2 +b 2 或 a 2 =b 2 或c 2 = a 2 +b 2 且 a 2 =b 2
    ∴ △ABC是直角三角形或等腰三角形或等腰直角三角形。