证明tan^2α-cot^2α/sin^2α-cos^2α=sec^2α+csc^2α
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证明tan^2α-cot^2α/sin^2α-cos^2α=sec^2α+csc^2α
(tan²a-cot²a)/(sin²a-cos²a)
=(sin²a/cos²a-cos²a/sin²a)/(sin²a-cos²a)
=(sin^4a-cos^4a)/sin²acos²a(sin²a-cos²a)
=(sin²a-cos²a)(sin²a+cos²a)/sin²acos²a(sin²a-cos²a)
=(sin²a+cos²a)/sin²acos²a
=1/cos²a+1/sin²a
=sec²a+csc²a
=(sin²a/cos²a-cos²a/sin²a)/(sin²a-cos²a)
=(sin^4a-cos^4a)/sin²acos²a(sin²a-cos²a)
=(sin²a-cos²a)(sin²a+cos²a)/sin²acos²a(sin²a-cos²a)
=(sin²a+cos²a)/sin²acos²a
=1/cos²a+1/sin²a
=sec²a+csc²a
证明tan^2α-cot^2α/sin^2α-cos^2α=sec^2α+csc^2α
证明 sin^2αtanα+cos^2αcotα+2sinαcosα=secαcscα
已知tan^2α+cot^2α+sec^2α+csc^2α=7,则sinαcosα
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