S=(1/1x3)+(1/3x5)+省略号+1/(2n-1)(2n+1)
S=(1/1x3)+(1/3x5)+省略号+1/(2n-1)(2n+1)
一道简便计算数学题1X2+2X3+3X4+4X5...+n(n+1)一1X2+2X3+3X4+4X5...+2013X2
C语言编程s(x)=x-x3/3!+x5/5!-x7/7!+……+(-1)n-1·x2n-1/(2n-1)!
用数学归纳法证明1/(1x3)+1/(3x5)+1/(5x7)…1/(2n-1)(2n+1)=n/(2n+1)
(x1,x2,x3,x4,x5,x6)来自正态总体N(0,1),Y=(x1+x2+x3)^2+(x4)^2+(x5)^2
sn=(2-3x5^-1)+(4-3x5^-2)+…+(2n-3x5^-n)要详解答案,急用!
解方程组X2+X3+X4=1 X1+X2+X3=5 X3+X4+X5=-5 X4+X5+X1=-3 X5+X1+X2=2
数列的前N项求和数列:1/(1X3),1/(3X5),1/(5X7),……,1/[(2n-1)(2n+1)]呃,这种类型
求前n项和1.1/(2X5),1/(5X8),1/(8X11)...2.2^2/(1X3),4^2/(3X5),6^2/
求数列1/1x2,1/2x3,1/3x4,1/4x5.的前n项和---
若多项式x4次方yn次方-2x3次方与-1/3x5次方-4y+1/5的次数相同,试探究n-2n+3n-4n+5n-6n+
)设X服从N(0,1),(X1,X2,X3,X4,X5,X6)为来自总体X的简单随机样本,Y=(X1+X2+X3+)^2