1x2+2x3+3x4+4x5+.+15x16
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/11/05 18:41:37
1x2+2x3+3x4+4x5+.+15x16
可看成通项公式an=n×(n+1)的前15项之和,
前n项和Sn=1×2+2×3+3×4+4×5+……+n×(n+1)
=(1^2+1)+(2^2+2)+(3^2+3)+…+(n^2+n)
=(1^2+2^2+3^2+…+n^2)+(1+2+3+…+n)
=1/6×n(n+1)(2n+1)+1/2×n(n+1)
=1/6×n(n+1)(2n+1+3)
=1/3×n(n+1)(n+2)
∴1×2+2×3+3×4+4×5+……+15×16=1/3×15×16×17=1360
前n项和Sn=1×2+2×3+3×4+4×5+……+n×(n+1)
=(1^2+1)+(2^2+2)+(3^2+3)+…+(n^2+n)
=(1^2+2^2+3^2+…+n^2)+(1+2+3+…+n)
=1/6×n(n+1)(2n+1)+1/2×n(n+1)
=1/6×n(n+1)(2n+1+3)
=1/3×n(n+1)(n+2)
∴1×2+2×3+3×4+4×5+……+15×16=1/3×15×16×17=1360
求齐次线性方程组x1+2x2+x3+x4+x5=1 2x1+4x2+3x3+x4+x5=2 -x1-2x2+x3+3x4
1分解因式:2x4-x3-13x2-15=?2.分解因式:x5+x4+x3+x2+x+1=?3分解因式:x4-4x2+6
解方程组X2+X3+X4=1 X1+X2+X3=5 X3+X4+X5=-5 X4+X5+X1=-3 X5+X1+X2=2
一道简便计算数学题1X2+2X3+3X4+4X5...+n(n+1)一1X2+2X3+3X4+4X5...+2013X2
已知数据x1,x2,x3,x4,x5的平均数是20,那么另一组数据x1,x2+1,x3+2,X4+3,X5+4的平均数
已知数据X1,X2,X3,X4,X5的平均数是X拔,则一组新数据X1+1,X2+2,X3+3,X4+4,X5+5的平均数
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1/1x2+1/2x3+1/3x4+1/4x5.1/2005x2006=?
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