化简f(x)=cos^2(x+π/12)+1/2sin2x
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/10/04 04:10:25
化简f(x)=cos^2(x+π/12)+1/2sin2x
f(x)=cos^2(x+π/12)+1/2sin2x
=1/2*[1+c0s(2x+π/6)]+1/2sin2x
=1/2+1/2(cos2xcosπ/6-sin2xsinπ/6)+1/2sin2x
=1/2+1/2cos2xcosπ/6-1/4sin2x+1/2sin2x
=1/2+1/2cos2xcosπ/6+1/4sin2x
=1/2+1/2(cos2xcosπ/6+sin2xsinπ/6)
=1/2+1/2cos(2x-π/6)
= 1/2[1+cos(2x-π/6)]
=cos^2(x-π/12)
=1/2*[1+c0s(2x+π/6)]+1/2sin2x
=1/2+1/2(cos2xcosπ/6-sin2xsinπ/6)+1/2sin2x
=1/2+1/2cos2xcosπ/6-1/4sin2x+1/2sin2x
=1/2+1/2cos2xcosπ/6+1/4sin2x
=1/2+1/2(cos2xcosπ/6+sin2xsinπ/6)
=1/2+1/2cos(2x-π/6)
= 1/2[1+cos(2x-π/6)]
=cos^2(x-π/12)
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
已知函数f(x)=[cos(x+π/12)]^2,g(x)=1+1/2sin2x.求:
已知函数f(x)=cos^2(x+12/π),g(x)=1+sin2x/2
f(x)=cos平方(x+派/12)+1/2sin2x,求化简
已知函数f(x)=sin2x+2cos*2x
已知函数 f(x)=sin2x+√2cos(x-π/4) 求f(x) 值域
已知函数f(x)=cos(π/3+x)cos(π/3 -x),g(x)=1/2sin2x-1/4 (1)求f(x)的最小
已知函数f(x)=sin2x+2根号3sin(π/4+x)cos(π/4+x),(1),化简f(x)的表达式.并求出最小
设函数f(x)=sin²x+2sin2x+3cos²x 化简
已知函数f(x)=sin2x+cos(2x+π/6),其中x∈R
已知函数f(x)=cos²x,g(x)=1+1/2sin2x
已知函数f(x)=cos(2x-π3)+sin2x-cos2x.