计算tanπ/12 / (1-tan^2π/12)=
tan(π/12)+1/tan(π/12)=啥?
化简:tan(π/8)+1/tan(π/12)
数学tan(α-π/2)=1/2 tan(π+β)=3 则 tan(α+β)=?
tan(a+b)=3/4,tan(a-π/4)=1/2,那么tan(b+π/4)等于多少
已知A、B是锐角,求证(tan(π+A)+tan(-B))/(1/tan(3π-A)+tan(π/2-B))=tanA*
关于三角函数恒等变化1-1/2tanα-1/2tan(π/4-α)=2-1/2[(1+tanα+1/(1+tanα)]
已知tan(π/12+α)=根号2,tan(β-π/3)=2根号2,求tan(α+β)的值
已知tan(π/12+α)=根号2,tan(β-π/3)=2根号2.求tan(α+β-π/4)和tan(α+β)的值
tan=3,π
1)tan(x/2+π/4)+tan(x/2-π/4)=2tanx
已知tan(π/4+a)=-1/2,求[sin2a-2(cosa)^2]/1+tan a
已知tanα=2,求:(1)tan(α+π4)