复数(3+2i)/(2-3i)-(3-2i)/(2+3i)=
复数(4+3i)(2+i)=
复数1+3i/2+i=
复数 (3-i/1+i)^2=
复数(3+2i)/(2-3i)-(3-2i)/(2+3i)=
-2i+(1+2i)+(2-3i)=(1+i)的共轭复数为
设复数z满足i(z+i)=-3+2i(i为虚数单位),则z的实部是
复数z=1+2i,则复数1z−3i的虚部是( )
已知复数z=(1-i)^2+3(1+i)/2-i 求复数z
i是虚数单位,复数(3-i/1+i)2等于
复数3-3i/2-i
复数 (2+2i)/(2-3i)-(3-2i)/(2+3i)=?
复数除法 计算1+i/1-i,1/i,7+i/3+4i (-1+i)(2+i)/-i