1/(1×3×5)+1/(3×5×7)+1/(5×7×9)+1/(7×9×11)+...+1/(2001×2003×20
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/09/14 14:52:27
1/(1×3×5)+1/(3×5×7)+1/(5×7×9)+1/(7×9×11)+...+1/(2001×2003×2005)=?
1/(1×3×5)+1/(3×5×7)+1/(5×7×9)+1/(7×9×11)+...+1/(2001×2003×2005)
=1/4*(1/1*3-1/3*5)+1/4(1/3*5-1/5*7)+...+1/4(1/2001*2003-1/2003*2005)
=1/4(1/1*3-1/3*5+1/3*5-1/5*7+...+1/2001*2003-1/2003*2005)
=1/4(1/1*3-1/2003*2005)
=1/12-1/(2003*8020)
=1/4*(1/1*3-1/3*5)+1/4(1/3*5-1/5*7)+...+1/4(1/2001*2003-1/2003*2005)
=1/4(1/1*3-1/3*5+1/3*5-1/5*7+...+1/2001*2003-1/2003*2005)
=1/4(1/1*3-1/2003*2005)
=1/12-1/(2003*8020)
计算: 1+(-3)+5+(-7)+9+(-11)+...+2001+(-2003)+2005等于多少
题目(1)1+3+5+7+9+11+13+15+17+19+...+2001+2003=?
1/(1*3*5)+1/(3*5*7)+1/(5*7*9)+1/(7*9*11)+1/(9*11*13+)1/(11*1
计算1+(-3)+5+(-7)+9+(-11)+.+2001+(-2003)+2005按有理数的方法做
-1,-1/3,1/5,1/7,-1/9,-1/11,1/13,1/15.第2001个数是().
计算 1+(-3)+5+(-7)+9+(-11)+...+2001+(-2003)+2005
1+3+5+7+9+11+...+2001+2003结果为
计算1(-3)+5(-7)+9(-11)+.+2001+(-2003)
计算:1/1×3+1/3×5+1/5×7+1/7×9``````+1/2001×2003
(1)1-3+5-7+9-11+...-2011
计算:(1-3)*(3-5)*(5-7)*.*(2001-2003)*(2003-2005)
1/3*5+1/5*7+1/7*9+.+1/2001*2003