sin29π/6+cos(-29π/3)+tan(-25/4)
sin29/6π+COS(-29/3π)+tan(-25/4π)答案拜托了各位
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
sin(4π/3)*cos(25π/6)*tan(-3π/4)
sin(-4π/3)cos(-23π/6)tan(25π/4)=?
SIN(-7/6π),cos(15/4π),tan(-8/3π),tan(33/4π)
cos(19π/6)+tan(16π/3)=?
已知tanα/2=2,1.求tan(α+π/4)的值 2.(6sinα+cosα)/(3sinα-2cosα)的值
已知tanα/2=2求tan(α+π/4)的值(6sinα+cosα)/(3sinα-2cosα)的值
tan(a-4π)cos(π+a)sin^2(a+3π)/tan(3π+a)cos^2(2/5π+2)=0.5,求tan
求值sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-
sin25π/6+cos10π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)=
cosπ/3-tanπ/4+cosπ-sin3π/2 化简计算