(2lg2+lg3)/[1+(1/2)lg0.36+(1/3)lg8]等于什么
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(2lg2+lg3)/[1+(1/2)lg0.36+(1/3)lg8]等于什么
(2lg2+lg3)/[1+(1/2)lg0.36+(1/3)lg8]
=(lg2²+lg3)/[1+(1/2)lg0.6²+(1/3)lg2³]
=lg(4×3)/(lg10+lg0.6+lg2)
=lg12/lg12
=1
(注:lgM+lgN=lg(MN),lgN^n=nlgN,lg10=log(10)10=1)
再问: 1 (1/2)lg0.6² (1/3)lg2³是怎么化成lg10 lg0.6 lg2的?
再答: 1=log(10)10=lg10.....................log(a)a=1(a>0) (1/2)lg0.6² =(1/2)*2lg0.6=lg0.6....................课本上应该有类似的公式log(a)N^n=nlog(a)N (1/3)lg2³=(1/3)*3lg2=lg2
=(lg2²+lg3)/[1+(1/2)lg0.6²+(1/3)lg2³]
=lg(4×3)/(lg10+lg0.6+lg2)
=lg12/lg12
=1
(注:lgM+lgN=lg(MN),lgN^n=nlgN,lg10=log(10)10=1)
再问: 1 (1/2)lg0.6² (1/3)lg2³是怎么化成lg10 lg0.6 lg2的?
再答: 1=log(10)10=lg10.....................log(a)a=1(a>0) (1/2)lg0.6² =(1/2)*2lg0.6=lg0.6....................课本上应该有类似的公式log(a)N^n=nlog(a)N (1/3)lg2³=(1/3)*3lg2=lg2
2lg2+lg3除以1+1/2lg0.36+1/3lg8等于多少?
求1+1/2lg0.36+1/3lg8分之2lg2+lg3的值
(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)
第一题(2lg2+lg3)/(1+1/2lg0.36+1/3lg8)
计算(2lg2+lg3)/(1+0.5lg0.36+1/3lg8)
计算2lg2+lg3/1+1/2lg0.36+lg8如题
高一数学,麻烦大家了2lg2+lg3--------------------的值1+0.5lg0.36+(1/3)lg8
计算下列公式 (1)(2lg2+lg3)/(1+1/2lg0.36+1/3lg8) (2) lg5^2+2/3lg8+l
(lg8+lg100)lg5+3(lg2)^2+lg6^-1+lg0.006
(lg8+lg1000)lg5+3(lg2)^2+lg^-1+lg0.006
计算 (2lg2+lg3)/(1+lg0.6+lg2)
求2lg2+lg3/1+1/2lg.36+1/3lg8的值