log2 3=a,那log3 2=?
log2(3)+log3(5)+log3(2)=?
log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2)
log2 3×log3 7=log2 7
已知log3^2=a则log2^9等于多少
若a=log2 3.b=log3 2,c=log1/3 2.d=log2 1/3
若a=log2 3,b=log3 2,c=log4 6比较大小
log2 4=2log3 9=3
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
设a=log3π,b=log2根号3,c=log3根号2,则a,b,c,的大小关系为
设a=log3π,b=log2根号3,c=log3根号2则它们之间的大小关系