若a=log2 3.b=log3 2,c=log1/3 2.d=log2 1/3

若a=log2 3.b=log3 2,c=log1/3 2.d=log2 1/3 log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=? log2(log0.5(log2a))=0 log3(log1/3 (log3 b))=0 a,b的大小关系为?R log2(3)+log3(5)+log3(2)=? log2 3×log3 7=log2 7 若a=log2 3,b=log3 2,c=log4 6比较大小 设a=log1/3 2 b=log2 3 c= 1/2 ^0.3 比较a=log1/3(2),b=log2(3),c=(1/2)^0.3 log2[log1/2(log2x)]=log3[log1/3(log3y)]=0 比较XY的大小 已知a=log1/2(5),b=log2(3),c=1,d=3^-0.2,求a,b,c,d的大小关系 log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2) log2(a)=log3(b)=log5(c)