已知数列an满足(an+1-an)(an+1+an)=9),且a1=2,a>0.
已知a>0.数列{an}满足a1=a,an+1=a+ 1/an,(n=1,2…..),an极限存在,an>0.
已知一个数列{An}满足递推公式:An=3A(角标n-1)(n≥2),且A1=4,求数列{An}通项
已知数列an满足条件a1=-2 a(n+1)=2an/(1-an) 则an=
已知数列{an}满足:a1=1,且an-a(n-1)=2n.求a2,a3,a4.求数列{an}通项an
已知数列{an}满足an+1=an+3n+2,且a1=2,求an.
已知数列an满足an=1+2+...n,且(1/a1)+(1/a2)+...(1/an)
已知数列{an}满足a1=1,an+1=2an+1 1)求证:数列{an+1}为等比数列; 2) 求{an}的通项an
已知数列{An}满足:A1=3 ,An+1=(3An-2)/An,n属于N*.1)证明:数列{(An--1)/(An--
已知数列{an}满足:a1=3,an+1=(3an-2)/an ,n∈N*.(Ⅰ)证明数列{(an-1)/an-2
已知数列an满足,a1=1,an>0且a(n+1)×更号下(4+1/an^2)=1(n∈N+)
在数列an中,a1=1,且满足a(n+1)=3an +2n,求an
已知数列(an)满足an+1=2an+3×2∧n,a1=2求an