算式化简π [(x+y)÷2]² ÷ 2 - [ π (x÷2)² ÷2]-[ π (y÷2)&su
化简再求值[(x²+y²)²-4x²y²]÷(x²-y&su
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
先化简,再求值:(x²)/(x²-2xy+y²)÷(x²+2xy+y²)/(x&
「(x²+y²)-(x-y)²+2y(x-y)」÷4y,其中2x-y=18
已知2x-y=10 【(x²+y²)-(x-y)²+2y(x-y)】÷4y 过程
2x-y=10 【(x²+y²)-(x-y)²+2y(x-y)】÷4y
分式的除法运算x²-4y²/x²+y²+2xy÷2y+x/x²+xy
分式的乘除法计算::x²-4y²/x²+2xy+y²÷x+2y/x²+
1、(4x²y-2x³)÷(-2x)²
[(x+2y)²-(x+y)(3x-y)-5y²]÷(2x),其中x,y满足x²+4x+y
用分式表示2x²y(x-y)÷[12xy²(y-x)]的商,并约分