已知log7(2√2+1)+log2(√2-1)=a,则log7(2√2-1)+log2(√2+1)=_______.
数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(
求下列函数的定义域(1)y=1/log2 X(2) y=log7(1/1-3x)(3) y=√log3 X
已知log7[log3(log2∧x)]=0,那么x∧-1/2等于
求下列函数的定义域 (1)y=1/log2 X (2) y=log7(1/1-3x) (3) y=
计算log^2 (log2^16)+7^(log7^49)-2log25^125的值
求下列函数的定义域(1)y=1/log2^x(2)y=log7(1/1-3x) (3)=根号下log三分之一
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
求值 3^2-log3(2)= log7(log5(log2(32)))=?
log3 √27+lg25+lg4+7的log7 2幂+(-9.8)º= 13/2 由其是7的log7 2幂.
log2(√1/48)+log2 12-1/2log2 (24)-1/3
比较a=2^0.8,b=log7^6,c=log2^0.8大小
Log2√(7/48) +log2 12 -(1/2)log2 42