计算log^2 (log2^16)+7^(log7^49)-2log25^125的值
计算log^2 (log2^16)+7^(log7^49)-2log25^125的值
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
高中数学对数计算求值(log2 125+log4 25+log8 5)*(log125 8+log25 4+log5 2
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
log(7) 2 / log7 10 =lg50
(log5根号2*log49 81)/(log25 1/3*log7 4开3次方)=?
数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(
(log2底5+log4底0.2)(log4底2+log25底0.4)的值是
log10是什么?log 75 - log 3 + log 4=log25+log3-log3+2log2=2log5+
求下列函数的定义域(1)y=1/log2^x(2)y=log7(1/1-3x) (3)=根号下log三分之一
(log5根号2底乘以log根号7底3 )/log根号5底3分之1乘以log7底4的立方根
(log5根号2*log49^81)/(log25^(1/3)*log7^立方根4)