(log2底5+log4底0.2)(log4底2+log25底0.4)的值是
(log2底5+log4底0.2)(log4底2+log25底0.4)的值是
(log2^5+log4^0.2)(log5^2+log25^0.25)化简
2^log4底12减3^log9底27加5^log25底1/3的值
求值(log2 5+log4 1/5)(log5 2+log25 1/2)
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)]
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
log2(12)-log4(9)的值是
运用对数换底公式化简log2(3)*log3(4)*log4(5)*log5(2),
log2为底3的对数,log4为底2的对数,log2为底5的对数,log0.5为底3的对数大小关系为?
question:利用对数的换底公式简化下列值 log2,3*log3,4*log4,5*log5,2 (注:,前面的为
高中数学对数计算求值(log2 125+log4 25+log8 5)*(log125 8+log25 4+log5 2