1.求抛物线方程 2.求直线方程
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/08/24 02:33:23
1.求抛物线方程 2.求直线方程
![](http://img.wesiedu.com/upload/a/ed/aedd65a12efa43edc7c6023024c587b2.jpg)
![](http://img.wesiedu.com/upload/a/ed/aedd65a12efa43edc7c6023024c587b2.jpg)
y^2=2px
2^2=2p*2
p=1
y^2=2x
y=kx+2
yM*yN=(k*xM+2)*(k*xN+2)=k^2*xM*xN+2k*(xM+xN)+4
(kx+2)^2=2x
(k^2)*x^2+(4k-2)x+4=0
xM+xN=(2-4k)/k^2,xM*xN=4/k^2
k(OM)*kON)=-1
(yM/xM)*(yN/xN)=-1
xM*xN+yM*yN=0
xM*xN+k^2*xM*xN+2k*(xM+xN)+4=0
(1+k^2)*xM*xN+2k*(xM+xN)+4=0
(1+k^2)*(4/k^2)+2k*(2-4k)/k^2+4=0
k=-1
y=-x+2
2^2=2p*2
p=1
y^2=2x
y=kx+2
yM*yN=(k*xM+2)*(k*xN+2)=k^2*xM*xN+2k*(xM+xN)+4
(kx+2)^2=2x
(k^2)*x^2+(4k-2)x+4=0
xM+xN=(2-4k)/k^2,xM*xN=4/k^2
k(OM)*kON)=-1
(yM/xM)*(yN/xN)=-1
xM*xN+yM*yN=0
xM*xN+k^2*xM*xN+2k*(xM+xN)+4=0
(1+k^2)*xM*xN+2k*(xM+xN)+4=0
(1+k^2)*(4/k^2)+2k*(2-4k)/k^2+4=0
k=-1
y=-x+2