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已知tanx=2 则sinxcosx+cos2x=?
求证(1-2sinXcosX)/(cos2X-sin2X)=(1-tanX)/(1+tanX)
已知tanx=2,求2sin2x-sinxcosx+cos2x的值.
(1/2)已知X,Y满足sinXcosX分之1-cos2X=1,tan(X-Y)=-3分之2.(1)求tanX的值 (2
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已知1+tanx/1-tanx=3 求sin2x+2sinx·cosx-cos2x/sin2x+2cos2x
已知tanx=2,求sinxcosx
已知(sinx+cosx)/(sinx-cosx)=2.求①tanx ②sin2x-2sinxcosx/cos2x-3s
已知tanx=2求(sin2x+cos2x)/(cos2x-sin2x)
已知1+sinx+cosx+sin2x+cos2x=0,求tanx
已知sin(x-45°)=√2/4.求(1)sinxcosx值,(2)求tanx+(1/tanx)值