设函数f(θ)=-1/2+(sin5θ/2)/(2sinθ/2),0

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/10/04 00:52:46

1.f(θ)=-1/2+(sin5θ/2)/(2sinθ/2)=-1/2+[sin(2θ)cos(θ/2)+cos(2θ)sin(θ/2)]/[2sin(θ/2)]
=-1/2+cos(2θ)/2+[2sinθcosθcos(θ/2)]/[2sin(θ/2)]
=-1/2+cos(2θ)/2+2cosθ[cos(θ/2)]^2=-1/2+[2(cosθ)^2-1]/2+cosθ(cosθ+1)
=2(cosθ)^2+cosθ-1 (0

设函数f(θ）=(2sinθcosθ+2.5)/(sinθ+cosθ),θ∈【0,派/2】,求函数f(θ)的最小值设函数f(x)=sin(2x+φ)(0 设函数f(x)=sin(2x+a)(0 设函数f(x)=sin(2x+φ)(-π 设函数 f(x)=sin(2x+y),(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(1/2x+φ)(0 ★ 设函数f(x) = [ (sinθ / 3) * x^3 ] + [ ((√3)cosθ / 2) * x^2 ] 设函数f(x)=x³+x,若当0≤θ≤π/2时,f(msinθ)+f(sinθ-sin²θ-2)＜0 高一数学函数已知函数f(x)=2sinθcosx-2sinθ