1/2x^4y^2-1/8x^2y^4

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/09 10:03:25

1/2x^4y^2-1/8x^2y^4
二分之一x的4次方y的2次方减八分之一的x的二次方y的4次方

1/2x^4y^2-1/8x^2y^4
=(1/2)(x^2y^2)(x^2-y^2/4)
==(1/2)(x^2y^2)[x^2-(y/2)^2]
=(1/2)(x^2y^2)(x+y/2)(x-y/2)

计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8 1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [（x+y)(x-y)-(x-y)^2+2y(x-y 9y=3x-(x-1),4(x+y)-(2x+4)=8y （x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3) 1 4(x-y+1)+y(y-2x) 已知4x=9y求(1)x+y/y (2)y-x/2x {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 把4（x-y+1)+y(y-2x)因式分解 4(x-y+1)+y(y-2x) 1、x(x-y)(x+y)-x(x+y)^2 求解;一 (x-8y)(x-y) 二 (Y+2)(Y-2)-(Y-1)(Y+5) 三 (3X+4)(3X-4)-(2X+ 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1