1 4(x-y+1)+y(y-2x)

来源：学生作业帮编辑：作业帮分类：综合作业时间：2024/11/05 23:36:34

1 4(x-y+1)+y(y-2x)
2 4x^4-13x^2+9
因式分解.

1、4(x-y+1)+y(y-2x)
=4x-4y+4+y²-2xy
=y²-4y+4-2xy+4x
=(y-2)²-2x(y-2)
=(y-2x-2)(y-2)
2、4x^4-13x^2+9
=(4x^4-4x²)-(9x²-9)
=4x²(x+1)(x-1)-9(x+1)(x-1)
=(4x²-9)(x+1)(x-1)
=(2x+3)(2x-3)(x-1)(x+1)

1、x(x-y)(x+y)-x(x+y)^2 1) (2x+5y)(2x-5y)(-4x^2-25y^2) 2) [（x+y)(x-y)-(x-y)^2+2y(x-y [(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 1 4(x-y+1)+y(y-2x) 把4（x-y+1)+y(y-2x)因式分解 4(x-y+1)+y(y-2x) (1)(x^2/x)-y-x-y （x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3) {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 已知4x=9y求(1)x+y/y (2)y-x/2x 计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8 化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1