x^3+y^3=x-y求证x^2+4y^2〈1
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
x,y属于R*,且x+y=1,求证:(1)(x+1/x)(y+1/y)≥25/4 (2)(x+1/x)^2+(y+1/y
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
已知x=1/3,y=-1/2,求代数式x-(x+y)+(x+2y)-(x+3y)+(x+4y)-(x+5y)+...-(
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y
若X,Y是整数,求证:(x+y)(x+2y)(x+3y)(x+4y)+y的四次方是一个完全平方数
[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3
先化简,再求值:[(x+y)(x-y)-(x-y)^2+2y(x-3y)]/(-4y),其中x=1,y=-2
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2
(x+2)(x+3) (x-4)(x+1) (y+4)(y-2) (y-5)(y-3)
9y=3x-(x-1),4(x+y)-(2x+4)=8y
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20