sin10π-√2cos(-19π/4)+tan(-13π/3)=
tan(a-4π)cos(π+a)sin^2(a+3π)/tan(3π+a)cos^2(2/5π+2)=0.5,求tan
cos(19π/6)+tan(16π/3)=?
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
已知tan(π/4+已知tan (π/4+a)=3 求 sin2a-2cos^2a-1的值
(1+tanα)/(1-tanα)=3+2√2,求cos^2(π-α)+sin(π+α)*cos(π-α)+2sin(α
证明[2-2sin(α+3π/4)cos(α+π/4)]/(cos^4α-sin^4α)=(1+tanα)/(1-tan
已知tan(π+α)=-1/3 tan(α+β)=[sin(π-2α)+4(cosα)^2]/[10(cosα)^2-s
知:tan(π+α)=-1/3,tan(α+β)=[sin2(π/2-α)+4(cosα)^2]/[10(cosα)^2
已知:tan(π+α)=-1/3,tan(α+β)=[sin2(π/2-α)+4(cosα)^2]/[10(cosα)^
已知【2+tan(θ-π)】/【1-tan(2π-θ】=-4,求(sinθ-3cosθ)(cosθ-sinθ)的值
cosπ/3-tanπ/4+cosπ-sin3π/2 化简计算