Imagine that you are a genetic counselor,and a couple planni
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Imagine that you are a genetic counselor,and a couple planning to start a family comes to you for information.Charles was married once before,and he and his first wife had a child with cystic fibrosis.The brother of his current wife,Elaine,died of cystic fibrosis.What is the probability that Charles and Elaine will have a baby with cystic fibrosis?(Neither Charles nor Elaine has cystic fibrosis.)
题目大致意思:假若你是个遗传顾问,那么一对准夫妻向你咨询一些问题.男方Charles结果一次婚,和前期有过一个患病(cystic fibrosis)的孩子.女方elaine的哥哥死于该病.问他们如果生一个孩子患病的可能有多大?(前提是男女方都没患该病).
1、首先男方必然带有该基因,孩子才可能患病.那么可以先确定的是男方的基因型为Cc.
2、女方的哥哥死于该病,说明父母都有该基因.但是有一个问题,该病会导致不孕.如果考虑这个因素的话,说明女方父母都不会是纯合,应该都是Cc.那么女方的基因型有可能是CC或者Cc.不考虑的话你就按一楼的要考虑女方父母的基因型的问题,但是一楼有一个明显的失误是女方不换病,所以不会有可能是dd.
3、也就是说男方贡献c的几率是1/2,女方贡献c的几率是1/4.所以应该是1/8.或者你分情况讨论,女方是显性纯合的话患病几率为0,是杂合的话,几率为1/4,所以患病的几率为(0+1/4)*1/2=1/8,这个1/2就是说女方是Cc的几率.
1、首先男方必然带有该基因,孩子才可能患病.那么可以先确定的是男方的基因型为Cc.
2、女方的哥哥死于该病,说明父母都有该基因.但是有一个问题,该病会导致不孕.如果考虑这个因素的话,说明女方父母都不会是纯合,应该都是Cc.那么女方的基因型有可能是CC或者Cc.不考虑的话你就按一楼的要考虑女方父母的基因型的问题,但是一楼有一个明显的失误是女方不换病,所以不会有可能是dd.
3、也就是说男方贡献c的几率是1/2,女方贡献c的几率是1/4.所以应该是1/8.或者你分情况讨论,女方是显性纯合的话患病几率为0,是杂合的话,几率为1/4,所以患病的几率为(0+1/4)*1/2=1/8,这个1/2就是说女方是Cc的几率.
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