若数列{an}满足a1=1,且[1/a(n+1)]-(1/an)=1,则a1a2+a2a3+.+a2010a2011=
已知数列an满足a1=1,a(n+1)=an/{3(an)+1} Sn=a1a2+a2a3+.+an(an+1),求Sn
数列{an}满足a1=1,1/2an=1/2an+1(n∈N※),若a1a2+a2a3+...+anan+1>16/33
已知数列{an}满足a1=1,An+1=an/1+2an(n属于N*) 问若若a1a2+a2a3+……+anan+1>1
(a1+a2+a3+.+an)^2=a1^2+a2^2+.+an^2+2(a1a2+a2a3+...+a(n-1)an)
若数列an为等比数列,且a1=2 q=3 求sn=1/a1a2+1/a2a3+.+1/ana(n+1)
已知函数F(x)=2x/(x+2)数列An满足A1=4/3,A(n+1)=F(An)记Sn=A1A2+A2A3+.+An
数列a1=1,an=an+1(1+2an)求证数列an分之一等差数列,若a1a2+a2a3+..+anan+1大于33分
在数列{an}中,若a1=1,且对所有n∈N+满足a1a2…an=n2,则a3+a5=( )
已知数列{an}的前n项和Sn=n²+n,求和1/a1a2+1/a2a3+.+1/an-1*an+1/an*a
已知数列{an},若1/a1a2+1/a2a3+…+1/anan-1=n/anan+1,求证{an}为等差数列.
已知数列an的前n项和是Sn=n^2,则1/a1a2+1/a2a3+...+1/a(n-1)an=?
【急】已知数列an满足1/a1a2+1/a2a3+……1/an-1an=(n-1)/a1an,求证为等差数列