求证:(1-2sin2xcos2x)/(cos^2x-sin^2x)=(1-tan2x)/(1+tan2x)
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求证:(1-2sin2xcos2x)/(cos^2x-sin^2x)=(1-tan2x)/(1+tan2x)
因为1=cos^2x+sin^2x 故1-2sin2xcos2x=cos^2x+sin^2x-2sin2xcos2x =(cos2x-sin2x)^ 故(1-2sin2xcos2x)/(cos^2x-sin^2x)=(cos2x-sin2x)^ /(cos2x-sin2x)(cos2x+sin2x) =(cos2x-sin2x) / (cos2x+sin2x) =(1-tan2x)/(1+tan2x)
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