lim(n→∞){2^n[sin(x/2^n)]}
Lim(n→∞) 2的n次方sin x/2的n次等于多少?
求极限lim(x→∞)(1/n+2/n+3/n..+n/n)
(n→∞)时lim(2∧n)*(sin(x/2∧n))的极限
计算极限lim(n→∞){1+ sin[π√(2+4*n^2)]}^n
求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞)
求极限lim(1/n)*[(sin(pi/n)+sin(2pi/n)+.+sin(n*pi/n)] n->无穷
求lim n→∞ (1+2/n)^n+3
高数求极限n趋于无穷大时,lim (1/n - sin(1/n))/ (1/n^2),lim (1/n - sin(1/
lim(x→∞)(n/2^n)=lim(x→∞)(1/(ln2*2^n)) 这个是咋么算出来的,
求极限 lim Sin[pi*√(n^2+1)] n→∞
lim(x→∞)1+2+3+…+n/(n+2)(n+4)=?
求极限lim(n->∞)2^n*sin(π/2^n)