5^(log25((lg2^2)+lg5/2))

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/09/04 12:38:29

1
5^(log25(lg4*5/2))
=5^(log25(lg10))
=5^(log25 1)
=5^0
=1

lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5 lg^2 5+lg2*lg5+lg2=? 计算：(lg5)^2 +lg2 *lg5 (lg5)^2+lg5.lg2= lg2(1+lg5)+(lg5)^2 (lg2)^2+lg2*lg5+(lg5)^2= 2lg2（lg2+lg5)+2lg5得数 (lg5)平方+2*lg5*lg2+(lg2)平方计算 lg5^2+lg2*lg5+lg2 lg2 2+lg4*lg5+lg2 2lg5*lg2= 3+lg5+(lg2)^2