求lim【1/(n2+π)+1/(n2+2π)+...+1/(n2+nπ)】(n趋向于正无穷)
求lim【1/(n2+π)+1/(n2+2π)+...+1/(n2+nπ)】(n趋向于正无穷)
求 证Lim ( n/ n2+1) + (n/ n2+2) +( n/ n2+3).+(n/n2+n)当n趋向无穷时的极
求极限lim((n+1)/(n2+1)+(n+2)/(n2+2)+...+(n+n)/(n2+n)),n趋近无穷
大一求极限lim(n/(n2+1)+n/(n2+2^2)+……+n/(n2+n2))
1.求lim[1/(n2+n+1)+2/(n2+n+2)+.+n/(n2+n+n)][n趋于无穷][n2为n的平方]
高数极限题:用极限定义,证明:lim n2+n+6/n2+5=1 n趋向于无穷.其中n2就是n的平方
计算lim(1/n2+1+2/n2+1+3/n2+1+...+n/n2+1)
Lim bn( n趋向无穷大) [( 1/ n2+1) + (2/ n2+1) +( 3/ n2+1) +.(2n/ n
请问如何证明lim(n→∞)[n/(n2+n)+n/(n2+2n)+…+n/(n2+nn)]=1,
如何证明lim(n~正无穷)1/n2=0
求极限:Lim(1+1/n-1/n^2)^n n趋向于正无穷
lim(√(n2+2n)-n) 当n趋向无穷时