求极限lim(n→∞)(3n^2-n+1)/(2+n^2)?

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/11/06 01:48:41

lim(n→∞)(3n^2-n+1)/(2+n^2)
=lim(n→∞)(3n^2+6-6-n+1)/(2+n^2)
=lim(n→∞)[3(n^2+2)-(5+n)]/(2+n^2)
=lim(n→∞)[3-(5+n)/(2+n^2)]
=3

求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞) lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限求极限lim(x→∞)（1/n+2/n+3/n..+n/n）求极限lim(n→∞)(3n^2-n+1)/(2+n^2)? 求极限lim(-2)^n+3^n/(-2)^[n+1]+3^[n+1] (x→∞) 求极限：lim(n→∞)[（3n+1 ）/（3n+2）]^(n+1) lim（n→∞) （(2n!/n!*n)^1/n的极限用定积分求求极限n~∞,lim(n+1)/2n 求一道极限题lim[(a^1/n+b^1/n)/2]^n n→∞ lim（1/n+2^1/n）^n n→∞求详解!高数极限求极限 lim(n→∞)[根号(n^2+4n+5)-(n-1)] = 求极限 lim(n->无穷)[(3n^2-2)/(3n^2+4)]^[n(n+1)]