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英语数学题,求翻译求解答

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英语数学题,求翻译求解答
A father in his will left all his money to his children in the following manner:
$1000 to the first born and 1/10 of what then remains, then
$2000 to the second born and 1/10 of what then remains, then
$3000 to the third born and 1/10 of what then remains, and so on.
When this was done each child had the same amount. How many children were there?
问:一个父亲在他的遗嘱中把他所有的财产分给孩子们,具体如下:
老大拿去1000和剩余财产的十分之一,老二拿去2000和剩余财产的十分之一,老三拿去3000和剩余财产的十分之一,以此类推.当这些结束后,所有孩子得到相同数目财产.共有多少孩子?
设有x财产,则老大分的1000+(x-1000)/10
老二分的(x-2000-(1000+(x-1000)/10))/10+2000
两者相等,所以解得x=81000,则每个孩子分的1000+(81000-1000)/10=9000
因此共有9个孩子
鉴定完毕