{x+y/2+x-y/3=6 4(x+y)-3(x-y)=0 用加减消元法解方程组
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{x+y/2+x-y/3=6 4(x+y)-3(x-y)=0 用加减消元法解方程组
(x+y)/2+(x-y)/3=6……①
4(x+y)-3(x-y)=0 …… ②
由①:
3(x+y)+2(x-y)=36
3x+3y+2x-2y=36
5x+y=36……③
由②:
4x+4y-3x+3y=0
x+7y=0…… ④
④×5-③:
5x+35y-(5x+y)=0-36
34y=-36
y=-18/17
将y=-18/17带入④
x=0-7y=0-[7×(-18/17)]=0+126/17=126/17
方程组的解为:x=126/17,y=-18/17
4(x+y)-3(x-y)=0 …… ②
由①:
3(x+y)+2(x-y)=36
3x+3y+2x-2y=36
5x+y=36……③
由②:
4x+4y-3x+3y=0
x+7y=0…… ④
④×5-③:
5x+35y-(5x+y)=0-36
34y=-36
y=-18/17
将y=-18/17带入④
x=0-7y=0-[7×(-18/17)]=0+126/17=126/17
方程组的解为:x=126/17,y=-18/17
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