∫ [cos^3(x)]/[sin^2 (x)]dx

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/10/04 11:01:58

∫ [cos^3(x)]/[sin^2 (x)]dx
=积分:(cos^2x)/(sin^2x)dsinx
=积分:(1-sin^2x)/sin^2x)dsinx
=积分;1/sin^2xdsin^2x-积分1dsinx
=-1/sinx-sinx+C

∫sin(x) cos^2(x)dx 微积分求解：∫sin^3 (x) cos^2 (x) dx 求积分：∫sin^2 (x) /cos^3 (x) dx ∫ [cos^3(x)]/[sin^2 (x)]dx ∫sin^3(x)cos^2(x)dx= ∫(cos^3x/sin^2x)dx ∫dx/[sin^2(x/2)cos^2(x/2)] ∫sin^(3)x cos^(3)x dx ∫sin^2(x)cos^2(x)dx ∫dx/cos^2X+4sin^2X 求不定积分：∫(sin x/cos^3 x)dx ∫ sin^4(x)cos^3(x)dx