就这几道题,谢谢你了1 lim(1-[√(1+m)]/x) X趋向02 lim((x-3)/x-1) x趋向无穷3 y=
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/07/13 22:14:20
就这几道题,谢谢你了
1 lim(1-[√(1+m)]/x) X趋向0
2 lim((x-3)/x-1) x趋向无穷
3 y=x^2lnx 求 dy/dx
4 ∫(5√(1+x^2)+2/(1+x^2))
5 ∫((2x^2)+3/x^(2+1))/dx
6 ∫((2x^2+3)/(x^2+1))dx
7 ∫f(x)dx=e^xcos2x+c
1 lim(1-[√(1+m)]/x) X趋向0
2 lim((x-3)/x-1) x趋向无穷
3 y=x^2lnx 求 dy/dx
4 ∫(5√(1+x^2)+2/(1+x^2))
5 ∫((2x^2)+3/x^(2+1))/dx
6 ∫((2x^2+3)/(x^2+1))dx
7 ∫f(x)dx=e^xcos2x+c
1 lim(1-[√(1+m)]/x) X趋向0=∞
2 lim((x-3)/x-1) x趋向无穷=1
3 y=x^2lnx 求 dy/dx
dy/dx=y'dx=(2xlnx+x)dx
4 ∫(5√(1+x^2)+2/(1+x^2))dx=∫5(1+x^2)^(-0.5)dx+∫2/(1+x^2)dx
则原式=5ln(x+√1+x^2)+2arctanx+C
5 ∫((2x^2)+3/x^(2+1))dx=∫2x^2dx+∫3/x^3dx=(1/3)x^3-(3/4)/x^4+C
6 ∫((2x^2+3)/(x^2+1))dx=∫[2+1/x^2+1]dx=2x+arctanx+C
7 ∫f(x)dx=e^xcos2x+c
f(x)=[ ∫f(x)dx]'=(e^xcos2x+c)'=e^xcos2x-2e^xsin2x
2 lim((x-3)/x-1) x趋向无穷=1
3 y=x^2lnx 求 dy/dx
dy/dx=y'dx=(2xlnx+x)dx
4 ∫(5√(1+x^2)+2/(1+x^2))dx=∫5(1+x^2)^(-0.5)dx+∫2/(1+x^2)dx
则原式=5ln(x+√1+x^2)+2arctanx+C
5 ∫((2x^2)+3/x^(2+1))dx=∫2x^2dx+∫3/x^3dx=(1/3)x^3-(3/4)/x^4+C
6 ∫((2x^2+3)/(x^2+1))dx=∫[2+1/x^2+1]dx=2x+arctanx+C
7 ∫f(x)dx=e^xcos2x+c
f(x)=[ ∫f(x)dx]'=(e^xcos2x+c)'=e^xcos2x-2e^xsin2x
就这几道题,谢谢你了1 lim(1-[√(1+m)]/x) X趋向02 lim((x-3)/x-1) x趋向无穷3 y=
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